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McGraw Hill Integrated II, 2012

MH

McGraw Hill Integrated II, 2012 View details

Study Guide and Review

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Exercise 9 Page 607

Solve for the variable by using cross products.

49

Practice makes perfect

To solve the proportion, we will start by using cross products. Remember that we will need to treat the expressions x+8 and 2x-3 as single quantities in the cross multiplication process.

x+8/6=2x-3/10

Cross multiply

(x+8)10=6(2x-3)

From here, we will continue solving for x by using the Distributive Property and the Properties of Equality.

(x+8)10=6(2x-3)

▼

Solve for x

Distribute 10

10x+80=6(2x-3)

Distribute 6

10x+80=12x-18

LHS+18=RHS+18

10x+98=12x

LHS-10=RHS-10

98=2x

.LHS /2.=.RHS /2.

49=x

Rearrange equation

x=49

Subchapter links

1 Ratios and Proportions p.607

2 Similar Polygons p.607

3 Similar Triangles p.608

4 Parallel Lines and Proportional Parts p.608

5 Parts of Similar Triangles p.609

6 Similarity Transformations p.609

7 Scale Drawings and Models p.610