McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
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Exercise 29 Page 609

Recall that the ratio of the perimeters of the similar triangles is proportional to the scale factor.

≈633 miles

Practice makes perfect
Let's begin with recalling what we know about the perimeters of similar polygons. If two polygons are similar, then their perimeters are proportional to the scale factor between them. Since each distance on the map is proportional to the actual distance, the triangle formed by St.Louis, Springfield and Kansas City on the map is similar to the triangle formed by these cities in the real world.
Therefore, we can use the perimeter of the triangle on the map to find the perimeter of the actual triangle. Let's start with evaluating the perimeter of the triangle on the map. 15in.+10in.+13in.=38in. Next we will use the fact that the scale of the map is 3in.= 50mi to create a proportion. Let P be the perimeter of the actual triangle. 3in./50mi=38in./P Finally, we will solve the above proportion using cross multiplication.
3/50=38/P
3* P=50*38
3P=1900
P=633.333...
P≈633
The perimeter of the actual triangle formed by these cities is approximately 633 miles.