Practice Test
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Notice that ∠SQR is an exterior angle to △ QRT, so you can apply the Exterior Angle Theorem.
Statements
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Reasons
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1. RQ bisects ∠SRT
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1. Given
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2. ∠SRQ ≅ ∠QRT
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2. Definition of angle bisector
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3. m∠SRQ = m∠QRT
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3. Definition of congruent angles
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4. ∠SQR is exterior to △ QRT
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4. From the diagram
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5. m∠SQR > m∠QRT
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5. Exterior Angle Theorem
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6. m∠SQR > m∠SRQ
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6. Substitution
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Since RQ bisects ∠SRT we have that ∠SRQ ≅ ∠QRT, which means that m ∠SRQ = m ∠QRT.
Therefore, by applying the Exterior Angle Theorem, we have that m ∠SQR > m ∠QRT but, since m ∠SRQ = m ∠QRT, we obtain that m ∠SQR > m ∠SRQ.
In the following table we summarize the proof we did before.
Statements
|
Reasons
|
1. RQ bisects ∠SRT
|
1. Given
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2. ∠SRQ ≅ ∠QRT
|
2. Definition of angle bisector
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3. m∠SRQ = m∠QRT
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3. Definition of congruent angles
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4. ∠SQR is exterior to △ QRT
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4. From the diagram
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5. m∠SQR > m∠QRT
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5. Exterior Angle Theorem
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6. m∠SQR > m∠SRQ
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6. Substitution
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