McGraw Hill Integrated II, 2012
MH
McGraw Hill Integrated II, 2012 View details
Mid-Chapter Quiz
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Exercise 14 Page 188

Use the given roots to write the equation in factored form. Then multiply and simplify to obtain the standard form.

Example Equation: 4x^2+23x-6=0

We can write a quadratic equation in factored form using the given roots. Then we will rewrite it in standard form by multiplying the factors. cc Factored Form:& a(x-p)(x-q)=0 Standard Form:& ax^2+bx+c=0 In the factored form, p and q are the roots of the equation. Since we are told the roots are - 6 and 14, we can partially write the factored form of our equation. a( x-( - 6 ) ) ( x-1/4 )=0 ⇕ a( x+ 6 ) ( x-1/4 )=0 Since a does not have any effect on the roots, we can choose any value. For simplicity and in order to have integer coefficients, we will let a=4. This will allow us to eliminate the fractional part when we distribute. 4( x+ 6) ( x-1/4 )=0 Finally, let's use the Distributive Property to obtain the standard form.
4( x+ 6 ) ( x-1/4 )=0
â–Ľ
Distribute 4
( x+ 6) (4)( x-1/4 )=0
( x+ 6 ) (4x-1)=0
â–Ľ
Multiply parentheses
x(4x-1)+ 6(4x-1)=0
4x^2-x+ 6(4x-1)=0
4x^2-x+ 24x-6=0
4x^2+23x-6=0
Please note that this is just one example of a quadratic function that satisfies the given requirements. There are infinite possible solutions.