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McGraw Hill Integrated II, 2012

MH

McGraw Hill Integrated II, 2012 View details

2. Complex Numbers

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Exercise 38 Page 182

Recall that sqrt(- a)= isqrt(a).

x = ± 5i

Practice makes perfect

To solve the given equation, let's first isolate x^2.

2x^2+50=0

LHS-50=RHS-50

2x^2=- 50

.LHS /2.=.RHS /2.

x^2=- 25

We cannot find any real square roots of a negative number, so we will need to use the fact that sqrt(- a)= isqrt(a) to solve for x.

x^2=- 25

sqrt(LHS)=sqrt(RHS)

x=± sqrt(- 25)

sqrt(- a)= isqrt(a)

x=± i sqrt(25)

Calculate root

x=± i * 5

Multiply

x=± 5i

Subchapter links

Exercises p.182-184