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McGraw Hill Glencoe Geometry, 2012

MH

McGraw Hill Glencoe Geometry, 2012 View details

6. Dilations

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Exercise 54 Page 681

Use the Properties of Equality to isolate x. Then recall that π is approximately 3.14.

72.7

Practice makes perfect

To find the value of x, we should first gather all of the variable terms on one side of the equation and all of the constant terms on the other side using the Properties of Equality. In this case, the variable term is already on the right-hand side of the equation, so we will start by dividing the equation by π.

228.4=π x

.LHS /π.=.RHS /π.

228.4/π=x

Rearrange equation

x=228.4/π

Now, remembering that π is approximately 3.14, we can substitute it for π and find the value of x.

x=228.4/π

π ≈ 3.14

x≈ 228.4/3.14

Calculate quotient

x≈ 72.73885...

Round to 1 decimal place(s)

x≈ 72.7

Subchapter links

Check Your Understanding p.677

H.O.T. Problems p.680

Standardized Test Practice p.681

Spiral Review p.681

Skills Review p.681