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Number in the First Dice | Number in the Second Dice | Sum |
---|---|---|
2 | 6 | 2+ 6=8 |
3 | 5 | 3+ 5=8 |
4 | 4 | 4+ 4=8 |
5 | 3 | 5+ 3=8 |
6 | 2 | 6+ 2=8 |
There are 5 outcomes.
Number on the First Dice | Number on the Second Dice | Sum | Number on the First Dice | Number on the Second Dice | Sum |
---|---|---|---|---|---|
1 | 2 | 1+ 2=3 | 4 | 1 | 4+ 1=5 |
1 | 4 | 1+ 4=5 | 4 | 3 | 4+ 3=7 |
1 | 6 | 1+ 6=7 | 4 | 5 | 4+ 5=9 |
2 | 1 | 2+ 1=3 | 5 | 2 | 5+ 2=7 |
2 | 3 | 2+ 3=5 | 5 | 4 | 5+ 4=9 |
2 | 5 | 2+ 5=7 | 5 | 6 | 5+ 6=11 |
3 | 2 | 3+ 2=5 | 6 | 1 | 6+ 1=7 |
3 | 4 | 3+ 4=7 | 6 | 3 | 6+ 3=9 |
3 | 6 | 3+ 6=9 | 6 | 5 | 6+ 5=11 |
We can also find the number of outcomes by using the Fundamental Counting Principle. We know that to have an odd sum the number on one dice has to be odd, whereas the number on the other dice has to be even. We have two cases.
Let's first find the number of outcomes of the first case.
We will identify the number of possible outcomes of each event.
Possible Outcomes | Type of the Outcomes | Number of Outcomes | |
---|---|---|---|
First Dice | 1,3,5 | Odd | 3 |
Second Dice | 2,4,6 | Even | 3 |
We will find the number of possible outcomes when the number on the first dice is odd and the number on the second dice is even. 3 * 3=9 There are 9 outcomes.
We will apply the same steps for Case II. This time, the number on the first dice will be even.
Possible Outcomes | Type of the Outcomes | Number of Outcomes | |
---|---|---|---|
First Dice | 2,4,6 | Even | 3 |
Second Dice | 1,3,5 | Odd | 3 |
We will use the principle to find the number of possible outcomes when the number on the first dice is even and the number on the second dice is odd. 3 * 3=9 This case also has 9 outcomes. We will find the total number of outcomes of the desired situation by adding up the outcomes that we found. 9+9=18