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McGraw Hill Glencoe Geometry, 2012

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McGraw Hill Glencoe Geometry, 2012 View details

Practice Test

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Exercise 6 Page 829

The area of a trapezoid is one half the product of the height and the sum of the bases.

Area: $2256 ft^{2}$

Practice makes perfect

Let’s find the area of the given figure, assuming that it is a trapezoid.

The area of a trapezoid is one half the product of its height and the sum of its bases. In the given figure, we can see that the lengths of the bases are

53

feet and

41

feet. The length of the height is

48

feet. We will now substitute these values into the formula to find the area of the trapezoid.

A = \frac{1}{2} h (b_{1} + b_{2})

SubstituteValues

Substitute values

A = \frac{1}{2} (48) (53 + 41)

▼

Evaluate right-hand side

Add terms

A = \frac{1}{2} (48) (94)

Multiply

A = \frac{1}{2} 4512

MoveRightFacToNumOne

$\frac{1}{b} \cdot a = \frac{a}{b}$

A = \frac{4 5 1 2}{2}

Calculate quotient

A = 2256

The area of the trapezoid is

2256

square feet.