Envision Math 2.0: Grade 8, Volume 1
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1. Rational Numbers as Decimals
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Exercise 16 Page 12

How can you rewrite 0.333333 ... with a line over the digits that repeat? How many digits will you write under the line?

No, see solution.

Practice makes perfect
We are asked if the number of repeating digits we use matters when writing a repeating decimal. To answer this question, let's take a look at a few examples of repeating decimals. &0.333333 ... &0.123123123 ... &0.25252525 ... Now, let's rewrite them with a line over the digits that repeat. &0.333333 ... = 0.3 &0.123123123 ... = 0. 123 &0.25252525 ... = 0.25

A line over 3 indicates that the number 3 repeats. Similarly, a line over 123 indicates that these three numbers repeat. Note that we could also rewrite them with more digits under the line. &0. 333333 ... = 0.3 = 0.333 &0. 1 2 3 1 2 3 1 2 3 ... = 0. 1 2 3 = 0.1 2 3 1 2 3 &0.2 52 52 52 5 ... = 0.2 5 = 0.2 5 However, we could not rewrite the second and third decimal as follows. &0. 1 2 3 1 2 3 1 2 3 ... ≠ 0.1 2 3 1 2 &0.2 52 52 52 5 ... ≠ 0.2 52 Let's take the first repeating decimal. We know that two options for writing this are 0.3 and 0.333. Let's rewrite each of the two forms as a fraction. Because we know they represent the same decimal, we can assign variable x to both of them.

First Equation Second Equation
x = 0.3 x = 0.333

Now, we will multiply each side of each equation by 10^d, where d is the number of repeating digits in the repeating decimal. In our case, we will multiply the first equation by 10^1 and the second one by 10^3.

First Equation Second Equation
10x = 3.3 1000x = 333.333

Next, we will subtract equivalent expressions of the variable and the repeating decimal from each side of each equation. From the left-hand sides we will subtract x. From the right-hand side of the first equation, we will subtract 0.3 and from the right-hand side of the second equation we will subtract 0.333. Then, we will solve each equation for x.

First Equation Second Equation
10x = 3.3 1000x = 333.333
10x -x = 3.3 - 0.3 1000x -x= 333.333 - 0.333
9x = 3 999x= 333
x = 3/9 x= 333/999

Note that if we divide the numerator and the denominator of the solution of the second equation by 111, we will get 39. x = 333/999 = 3/9 We can see that we ended up with the same fraction that represents x. The first time we used one repeating digit, and the second time three repeating digits. Therefore, the number of repeating decimals doesn't matter, because we will always end up with the same fraction.