Core Connections Integrated II, 2015
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Core Connections Integrated II, 2015 View details
2. Section 7.2
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Exercise 93 Page 409

Substitute 27 for x and 16 for y.

16

Practice makes perfect
We want to evaluate the given expression for the given values. Before we will substitute these values, let's simplify the given expression using Properties of Exponents. For this exercise we will begin by rearranging factors and using Product of Powers Property.
6x^(2/3)y^(1/4) * x^(- 1)y^(1/2)
6 * x^(2/3) * y^(1/4) * x^(- 1) * y^(1/2)
6 * x^(2/3) * x^(- 1) * y^(1/4) * y^(1/2)
6 * x^(2/3 - 1) * y^(1/4 + 1/2)
â–Ľ
Simplify
6 * x^(2/3 - 3/3) * y^(1/4 + 1/2)
6 * x^(2/3 - 3/3) * y^(1/4 + 2/4)
6 * x^(- 1/3) * y^(3/4)
Finally, we can evaluate the given expression for x=27 and y=16. To do this we should substitute these values into the expression and simplify as much as possible.
6 * x^(- 1/3) * y^(3/4)
6 * 27^(- 1/3) * 16^(3/4)
6 * ( 3^3 )^(- 1/3) * ( 2^4 )^(3/4)
â–Ľ
(a^m)^n=a^(m* n)
6 * 3^(3 (- 1/3)) * 2^(4 (3/4))
6 * 3^(3(- 1/3)) * 2^3
6 * 3^(- 1) * 2^3
6 * 1/3 * 2^3
â–Ľ
Simplify
2 * 3 * 1/3 * 2^3
2 * 1 * 2^3
2 * 2^3
2 * 8
16