Core Connections Integrated II, 2015
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Core Connections Integrated II, 2015 View details
2. Section 7.2
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Exercise 74 Page 402

Practice makes perfect
a Let's first plot AB and the three midpoints, C, D, and E.
To determine E we first have to find C. This will allow us to find D, which allows us to find E. We can find the midpoint of a segment with the Midpoint Formula.
M_C(x_1+x_2/2,y_1+y_2/2)
M_C(14+ 2/2,10+ 2/2)
â–Ľ
Simplify right-hand side
M_C(16/2,12/2)
M_C(8,6)
The midpoint of C is (8,6). Now we have enough information to find D.
M_D(x_1+x_2/2,y_1+y_2/2)
M_D(8+ 2/2,6+ 2/2)
â–Ľ
Simplify right-hand side
M_D(10/2,8/2)
M_D(5,4)
Finally, we have enough information to find E.
M_E(x_1+x_2/2,y_1+y_2/2)
M_E(8+ 5/2,6+ 4/2)
â–Ľ
Simplify right-hand side
M_E(13/2,10/2)
M_E(6.5,5)
The coordinates of E is (6.5,5).
b Let's label the distance between AC and BC as x.
This must mean that the distances AD and DC are both 0.5x.

Finally, the distances DE and EC are both 0.25x.

By adding the expressions for AD and DE and dividing by the distance of AB, we can get the fraction of the distance that E is from A to B.
0.5x+0.25x/0.5x+0.25x+0.25x+x
0.75x/2x
0.75/2
3/8
c By adding 38 of the vertical and horizontal distance between A and B to the x- and y-coordinates of A, we should end up at point E.

Let's add 38(12) to the x-coordinates of E and 38(8) to the y-coordinate of E. x_E:& 2+3/8(12) = 6.5 y_E:& 2 + 3/8(8) = 5 The coordinates of E is (6.5,5).