Core Connections Integrated II, 2015
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Core Connections Integrated II, 2015 View details
2. Section 7.2
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Exercise 94 Page 409

Practice makes perfect
a By the Triangle Angle Sum Theorem, we know that the sum of a triangles angles equal 180^(∘).
(4x+28^(∘)) + (x+19^(∘)) + (3x+13^(∘))=180^(∘) Let's solve for x in this equation.
(4x+28^(∘)) + (x+19^(∘)) + (3x+13^(∘))=180^(∘)
Solve for x
4x+28^(∘) + x+19^(∘) + 3x+13^(∘)=180^(∘)
8x+60^(∘)=180^(∘)
8x=120^(∘)
x=15^(∘)
b This is an isosceles triangle which means it's legs are congruent. From the diagram, we have been given expressions for the leg's length and because they are congruent, we can equate these expressions.
6k+3^(∘)=3k+18^(∘) Let's solve for k in this equation.
6k+3^(∘)=3k+18^(∘)
Solve for k
3k+3^(∘)=18^(∘)
3k=15^(∘)
k=5^(∘)
c From the diagram, we can make out two pairs of consecutive interior angles.
In both cases, the two sides cut by the third side are parallel. Therefore, we know by the Consecutive Interior Angles Theorem that they are supplementary. w+(4t+13^(∘))=180^(∘) w+(8t-23^(∘))=180^(∘) Since both equations equal 180^(∘), we can by the Substitution Property of Equality equate the left-hand side of the equations.
w+(4t+13^(∘))=w+(8t-23^(∘))
Solve for t
w+4t+13^(∘)=w+8t-23^(∘)
4t+13^(∘)=8t-23^(∘)
13^(∘)=4t- 23^(∘)
36^(∘)=4t
9^(∘)=t
t=9^(∘)
Having solved for t, we can also find w by substituting the value of t in either equation.
w+(8t-23^(∘))=180^(∘)
w+(8( 9^(∘))-23^(∘))=180^(∘)
Solve for w
w+(72^(∘)-23^(∘))=180^(∘)
w+49^(∘)=180^(∘)
w=131^(∘)
d With the given information, we can calculate the side labeled x by using the Law of Cosines.
c^2=a^2+b^2-2abcos C
x^2=43^2+43^2-2(43)(43)cos 71^(∘)
Solve for x
x^2=1849+1849-2(43)(43)cos 71^(∘)
x^2=1849+1849-1203.95103...
x^2=2494.04896...
x=± 49.94045...

x > 0

x= 49.94045...
x≈ 49.94