Chapter Closure
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Notice that ∠ BCE and ∠ CED are alternate interior angles. Since BC and ED are parallel segments, we know by the Alternate Interior Angles Theorem that these angles are congruent.
We see that CD is the intercepted arc of the central angle ∠ CED. Therefore, it must be that mCD is also 45^(∘).
Now we can find the measure of ∠ ACB by using the Interior Angles Theorem. 56^(∘)+65^(∘)+m∠ C=180^(∘) ⇓ m∠ C=59^(∘) Notice that ∠ ACB is the inscribed angle to the intercepted arc AB. By using the Inscribed Angles Theorem again, we can determine AB to be double that of ∠ ACB. That is, 2(59^(∘)) =118^(∘).