2. Section 7.2
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sqrt(85)≈ 9.2
sqrt(50)≈ 7.1
sqrt(22)≈ 4.7
x | x^2 | = |
---|---|---|
2 | 2^2 | 4 |
3 | 3^2 | 9 |
4 | 4^2 | 16 |
5 | 5^2 | 25 |
6 | 6^2 | 36 |
7 | 7^2 | 49 |
8 | 8^2 | 64 |
9 | 9^2 | 81 |
10 | 10^2 | 100 |
From the table, we see that 68 is between 64 and 81, which are perfect squares of 8 and 9. Therefore, sqrt(68) must be between 8 and 9
sqrt(64)
x | x^2 | = |
---|---|---|
2 | 2^2 | 4 |
3 | 3^2 | 9 |
4 | 4^2 | 16 |
5 | 5^2 | 25 |
6 | 6^2 | 36 |
7 | 7^2 | 49 |
8 | 8^2 | 64 |
9 | 9^2 | 81 |
10 | 10^2 | 100 |
Using the same logic from Part A, we can write intervals for each square root.
c|c
Comparing Roots & Comparing Exact Values [0.5em]
sqrt(4)< sqrt(5)
As we can see, our approximations are correct.