Core Connections Geometry, 2013
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Core Connections Geometry, 2013 View details
2. Section 3.2
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Exercise 111 Page 197

Practice makes perfect
a To find the equation of the line, we have to determine it's slope m and y-intercept b.
y=mx+ b Examining the diagram, we can identify where the line intercepts the y-axis.

The line intercepts the y-axis at (0,4) which means b= 4. To find the slope, we have to measure the vertical and horizontal distance between two points on the graph. Since the x- and y-intercepts of the graph are on the gridlines, we can use these to identify the slope.

Traveling between the y- and x-intercept requires that we move 8 steps horizontally in the positive direction and 4 steps vertically in the negative direction. With this, we can find the slope. rise/run=- 4/8 ⇔ m= - 1/2 Now that we have the slope and y-intercept, we can write our final equation. y= mx+b y= - 1/2x+4

b To write the equation of a line perpendicular to the line and through (-1,-3), we first need to determine the slope. Two lines are perpendicular when their slopes are opposite reciprocals. This means that the product of a given slope and the slope of a line perpendicular to it will be -1.
m_1*m_2=-1 From Part A, we know the slope of the line. By substituting this slope into the equation, we can solve for the slope of the perpendicular line, m_2.
m_1 * m_2 = - 1
- 1/2* m_2 = - 1
1/2* m_2 = 1
m_2=2
Any line perpendicular to the given line will have a slope of 2 which means we can write the equation in the following form. y=2x+b To find b, we substitute the coordinates of (- 1,- 3) in the equation and solve for b.
y=2x+b
- 3=2( - 1)+b
â–Ľ
Solve for b
- 3=- 2+b
- 1=b
b=- 1
The equation of the line through (- 1,- 3) that is perpendicular to the given line is y=2x-1.
c As in Parts A-C, we have to find the slope and y-intercept of the line that passes through the given points. When we have two points, we can use the Slope Formula to determine the slope.
m = y_2 - y_1/x_2 - x_1
m = 3 - 1/4 - ( - 1)
m = 3-1/4 + 1
m = 2/5
To complete the equation, we also have to find the y-intercept. We can do that by substituting one of the known points in the slope-intercept form.
y=2/5x+b
3=2/5( 4)+b
â–Ľ
Solve for b
3=8/5+b
15=8+5b
7=5b
7/5=b
b=7/5
Now we can complete the equation. y=2/5x+7/5
d If we assume that 1 hour is the minimum amount of time, the $15 charge can be viewed as a fixed cost for using the parking lot. After the first hour, the charge per hour is $ 7. This will be our slope. Let's write this as an equation.
C=15+7(t-1) where t≥ 1 Notice that if t= 1, we only have to pay the starting fee of $15 as 7( 1-1)=0 When the number of hours goes beyond 1, we pay the additional $ 7 per hour. Also, we could always rewrite the function by distributing 7.
C=15+7(t-1)
C=15+7t-7
C=8+7t