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Bus #41: Listening to MP3
Bus #41: Writing a letter
Bus #41: Reading a book
Bus #28: Listening to MP3
Bus #28: Writing a letter
Bus #28: Reading a book
Bus #55: Listening to MP3
Bus #55: Writing a letter
Bus #55: Reading a book
Bus #81: Listening to MP3
Bus #81: Writing a letter
Bus #81: Reading a book
Let's organize the sample space into a list. For each bus she can take, she can do three activities. Therefore, the list will have a total of 12 outcomes. Bus #41:& Listening to MP3 Bus #41:& Writing a letter Bus #41:& Reading a book Bus #28:& Listening to MP3 Bus #28:& Writing a letter Bus #28:& Reading a book Bus #55:& Listening to MP3 Bus #55:& Writing a letter Bus #55:& Reading a book Bus #81:& Listening to MP3 Bus #81:& Writing a letter Bus #81:& Reading a book
P=Number of favorable outcomes/Number of possible outcomes
#41, #55 and #81 This means 3 out of 4 outcomes are favorable and, therefore, the probability of taking an odd-numbered bus is 34 or 75 %.
Note that the number of the bus does not matter here. Any outcome that results in Renae not writing a letter is a favorable outcome. Let's highlight all of the favorable outcomes in our sample space.
There are 8 favorable outcomes out of 12 total outcomes. Therefore, the probability of Renae not writing a letter is 812= 23 or about 67 %.
Again, let's highlight the favorable outcomes in our sample space.
In this case, there is only 1 favorable outcome out of 12 total outcomes. Therefore, the probability of Renae taking the 28 bus and then reading a book is 112 or about 8 %.