Core Connections: Course 3
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Chapter Closure

Exercise 125 Page 144

Recall that a point is always written as an ordered pair, where the first coordinate is the x-value and the second coordinate is the corresponding y-value.

Table:

IN (x) - 2 - 1 0 1 2 3 4 5 6
OUT (y) - 9 - 7 - 5 - 3 - 1 1 3 5 7

Rule: y=2x-5

We want to create an x→ y table from the points on the provided graph. Then we can write a rule for the pattern in the table. Let's do it!

Table

Let's take a look at the graph.

When describing the location of a point, we need to determine how far along the x- and and y-axes the point is. Here are the coordinates of the points.

Now, recall that a point is always written as an ordered pair, where the first coordinate is the x-value and the second coordinate is the corresponding y-value. (- 2_x, - 9_y) Let's use this information to make our table.

IN (x) - 2 - 1 0 1 2 3 4 5 6
OUT (y) - 9 - 7 - 5 - 3 - 1 1 3 5 7

Rule

We are asked to wirte a rule for our table.

IN (x) - 2 - 1 0 1 2 3 4 5 6
OUT (y) - 9 - 7 - 5 - 3 - 1 1 3 5 7

We can see that as the x-value changes by 1, the corresponding y-values change by 2. This suggests that every input value x is multiplied by 2 in the process. Let's check to see if this is our pattern.

IN (x) - 2 - 1 0 1 2 3 4 5 6
2x 2(- 2)=- 4 2(- 1)=- 2 2(0)=0 2(1)=2 2(2)=4 2(3)=6 2(4)=8 2(5)=10 2(6)=12
OUT (y) - 9 - 7 - 5 - 3 - 1 1 3 5 7

Multiplying the input by 2 alone is not the complete pattern. However, we can see that the input value multiplied by 2 is always 5 more than the corresponding output value y. Let's try subtracting 5 in our rule and see if this is our pattern.

IN (x) - 2 - 1 0 1 2 3 4 5 6
2x-5 2(- 2)-5=- 9 2(- 1)-5=- 7 2(0)-5=- 5 2(1)-5=- 3 2(2)-5=- 1 2(3)-5=1 2(4)-5=3 2(5)-5=5 2(6)-5=7
OUT (y) - 9 - 7 - 5 - 3 - 1 1 3 5 7

We have found our rule! Let's write it down algebraically. 2x-5=y