Core Connections Algebra 1, 2013
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Core Connections Algebra 1, 2013 View details
1. Section 8.1
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Exercise 32 Page 378

Practice makes perfect
a To simplify the given expression, remember that the numerator of a rational exponent is the exponent of the expression, and the denominator is the index.
a^()1 n=sqrt(a) and a^() m n=sqrt(a^m) Let's simplify the expression!
125^(2/3)
125^(13 * 2)
(125^(13) )^2
(sqrt(125) )^2
â–Ľ
Calculate root
(sqrt(5 * 5 * 5) )^2
(sqrt(5^3) )^2
(5 )^2
25
b To simplify the given expression, remember that the numerator of a rational exponent is the exponent of the expression, and the denominator is the index.
a^()1 n=sqrt(a) and a^() m n=sqrt(a^m) Let's simplify the expression!
16^(1/2)

a^(1/2)=sqrt(a)

sqrt(16)
â–Ľ
Calculate root
sqrt(4 * 4)
sqrt(4^2)
4
c We want to simplify the given number. Notice that this expression has a negative exponent. When this is the case, the expression can be moved to the denominator and the exponent will become positive.
a^(- mn)= 1/a^()mn ⇒ 16^(- 1/2)=1/16^(1/2) We will split the base into perfect square factors to simplify this fraction. Because the denominator of the exponent is 2, this will allow us to simplify the rational exponent. Let's start!
1/16^(1/2)

a^(1/2)=sqrt(a)

1/sqrt(16)
â–Ľ
Calculate root
1/sqrt((4)(4))
1/sqrt(4^2)
1/4
d To simplify the given expression, remember that the numerator of a rational exponent is the exponent of the expression, and the denominator is the index.
a^()1 n=sqrt(a) and a^() m n=sqrt(a^m) Let's simplify the expression!
( 1/81 )^(1/4)
sqrt(1/81)
â–Ľ
Calculate root
sqrt(1/3 * 3 * 3 * 3)
sqrt(1/3 * 1/3 * 1/3 * 1/3)
sqrt((1/3)^4)
1/3