Sign In
Now we can determine the coordinates of these intercepts.
As we can see, the graph crosses the x-axis at the points (- 1, 0) and (3,0). Thus the x-intercepts are - 1 and 3. We can also notice that the graph intercepts the y-axis at the point (0,- 3), so the y-intercept is - 3.
Now we can determine the coordinates of this point.
As we can see, the graph crosses the x-axis at the point (2, 0). Thus, the x-intercept equals 2. We can also notice that the graph does not cross the y-axis, so there is no y-intercept.
x | - 5 | - 4 | - 3 | - 2 | - 1 | 0 | 1 | 2 |
---|---|---|---|---|---|---|---|---|
y | 8 | 4 | 0 | - 4 | 0 | 2 | 0 | - 4 |
Think of the point where the graph of a relation crosses the x-axis. The y-value of that ( x, y) coordinate pair is 0, and the x-value is the x-intercept. To find the x-intercept of the relation, we need to find the points where the y-value is 0.
x | - 5 | - 4 | - 3 | - 2 | - 1 | 0 | 1 | 2 |
---|---|---|---|---|---|---|---|---|
y | 8 | 4 | 0 | - 4 | 0 | 2 | 0 | - 4 |
We can see that the x-intercepts are - 3, - 1, and 1.
Let's use the same concept to find the y-intercept. Consider the point where the graph of the relation crosses the y-axis. The x-value of the ( x, y) coordinate pair at the y-intercept is 0. Therefore, we need to find the point where the x-value is 0.
x | - 5 | - 4 | - 3 | - 2 | - 1 | 0 | 1 | 2 |
---|---|---|---|---|---|---|---|---|
y | 8 | 4 | 0 | - 4 | 0 | 2 | 0 | - 4 |
We can see that the y-intercept is 2.
y= 0
Zero Property of Multiplication
Subtract term
.LHS /5.=.RHS /5.
x= 0
Zero Property of Multiplication
Subtract term
.LHS /(-2).=.RHS /(-2).