Core Connections Algebra 1, 2013
CC
Core Connections Algebra 1, 2013 View details
1. Section 8.1
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Exercise 18 Page 374

Practice makes perfect
a The x- and y-intercepts are points where the graph crosses the x- and y-axis, respectively. Let's identify them on the given graph.

Now we can determine the coordinates of these intercepts.

As we can see, the graph crosses the x-axis at the points (- 1, 0) and (3,0). Thus the x-intercepts are - 1 and 3. We can also notice that the graph intercepts the y-axis at the point (0,- 3), so the y-intercept is - 3.

b Let's identify the points where the given function crosses either the x - or the y -axis on the graph.

Now we can determine the coordinates of this point.

As we can see, the graph crosses the x-axis at the point (2, 0). Thus, the x-intercept equals 2. We can also notice that the graph does not cross the y-axis, so there is no y-intercept.

c We will identify the x - and y -intercepts of the given relation one at a time.
x - 5 - 4 - 3 - 2 - 1 0 1 2
y 8 4 0 - 4 0 2 0 - 4

Finding the x-intercept

Think of the point where the graph of a relation crosses the x-axis. The y-value of that ( x, y) coordinate pair is 0, and the x-value is the x-intercept. To find the x-intercept of the relation, we need to find the points where the y-value is 0.

x - 5 - 4 - 3 - 2 - 1 0 1 2
y 8 4 0 - 4 0 2 0 - 4

We can see that the x-intercepts are - 3, - 1, and 1.

Finding the y-intercept

Let's use the same concept to find the y-intercept. Consider the point where the graph of the relation crosses the y-axis. The x-value of the ( x, y) coordinate pair at the y-intercept is 0. Therefore, we need to find the point where the x-value is 0.

x - 5 - 4 - 3 - 2 - 1 0 1 2
y 8 4 0 - 4 0 2 0 - 4

We can see that the y-intercept is 2.

d To determine the x- and y-intercepts of a line, we need to substitute 0 for one variable, solve, then repeat for the other variable.

Finding the x-intercept

Think of the point where the graph of an equation crosses the x-axis. The y-value of that ( x, y) coordinate pair is 0, and the x-value is the x-intercept. To find the x-intercept of the equation, we should substitute 0 for y and solve for x.
5x-2y=40
5x-2( 0)=40
â–Ľ
Solve for x
5x-0=40
5x=40
x=8
An x-intercept of 8 means that the graph passes through the x-axis at the point ( 8,0).

Finding the y-intercept

Let's use the same concept to find the y-intercept. Consider the point where the graph of the equation crosses the y-axis. The x-value of the ( x, y) coordinate pair at the y-intercept is 0. Therefore, substituting 0 for x will give us the y-intercept.
5x-2y=40
5( 0)-2y=40
â–Ľ
Solve for y
0-2y=40
- 2y=40
y=- 20
A y-intercept of -20 means that the graph passes through the y-axis at the point (0, - 20).