a Do either of the equations have an isolated variable?
B
b Do either of the equations have an isolated variable?
C
c If either of the variable terms would cancel out the corresponding variable term in the other equation, you can use the Elimination Method to solve the system.
D
d If either of the variable terms would cancel out the corresponding variable term in the other equation, you can use the Elimination Method to solve the system.
A
a (- 2,5)
B
b (1,5)
C
c (- 12,14)
D
d (2,2)
Practice makes perfect
a In this system of equations, at least one of the variables has a coefficient of 1. Therefore, we will approach its solution with the Substitution Method. When solving a system of equations using substitution, there are three steps.
Isolate a variable in one of the equations.
Substitute the expression for that variable into the other equation and solve.
Substitute this solution into one of the equations and solve for the value of the other variable. For this exercise y is already isolated in one equation, so we can skip straight to solving!
The solution, or point of intersection, to this system of equations is the point (- 2,5).
b In this system of equations, at least one of the variables has a coefficient of 1. Therefore, we will approach its solution with the Substitution Method. When solving a system of equations using substitution there are three steps.
Isolate a variable in one of the equations.
Substitute the expression for that variable into the other equation and solve.
Substitute this solution into one of the equations and solve for the value of the other variable. For this exercise y is already isolated in one equation, so we can skip straight to solving!
The solution, or point of intersection, to this system of equations is the point (1,5).
c To solve a system of linear equations using the Elimination Method, one of the variable terms needs to be eliminated when one equation is added to or subtracted from the other equation. This means that either the x-terms or the y-terms must cancel each other out.
x+2 y=16 & (I) x+ y=2 & (II)We can see that the x-terms will eliminate each other if we subtract (II) from (I).
The solution, or point of intersection, of the system of equations is (- 12,14).
d To solve a system of linear equations using the Elimination Method, one of the variable terms needs to be eliminated when one equation is added to or subtracted from the other equation. This means that either the x-terms or the y-terms must cancel each other out.
2 x+3 y=10 & (I) 3 x-4 y=- 2 & (II)Currently, none of the terms in this system will cancel out. Therefore, we need to find a common multiple between two variable like terms in the system. If we multiply (I) by 3 and (II) by - 2, the x-terms will have opposite coefficients.
3(2 x+3 y)=3(10) - 2(3 x-4 y)=- 2(- 2)
⇕
6x+9 y=30 - 6x+8 y=4
We can see that the x-terms will eliminate each other if we add (I) to (II).
