Core Connections Algebra 1, 2013
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Core Connections Algebra 1, 2013 View details
2. Section 7.2
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Exercise 108 Page 352

Practice makes perfect
a Let's calculate the first four terms for Wade using the given information.
n 4(3)^n t(n)
1 4(3)^1 12
2 4(3)^2 36
3 4(3)^3 108
4 4(3)^4 324

Let's also calculate the first four terms for Dwayne.

n 12(3)^(n-1) t(n)
1 12(3)^(1-1) 12
2 12(3)^(2-1) 36
3 12(3)^(3-1) 108
4 12(3)^(4-1) 324

As we can see, both equations give the same sequence. Therefore, both forms of the equation are correct.

b A geometric sequence can be written in two ways. Either you start with the first term, or you start with the zero term.

First term:& t(n)= a_1b^(n-1) & a_1= first term [0.8em] Zeroth term:& t(n)= a_0b^n & a_0= zeroth term As we can see, Dwayne has written the equation in first-term form.

c Let's calculate the first four terms for Wade.
n 9.1+1.2n t(n)
1 9.1+1.2( 1) 10.3
2 9.1+1.2( 2) 11.5
3 9.1+1.2( 3) 12.7
4 9.1+1.2( 4) 13.9

Let's also calculate the first four terms for Dwayne.

n 10.3+1.2(n-1) t(n)
1 10.3+1.2( 1-1) 10.3
2 10.3+1.2( 2-1) 11.5
3 10.3+1.2( 3-1) 12.7
4 10.3+1.2( 4-1) 13.9

As we can see, both equations give the same sequence. Therefore, both forms of the equation are correct.

d Dwayne calls the equation first term form, because his equation starts with the first term of the sequence. We have to subtract 1 from n because if we substitute n=1 into the first term form we are left with a_1.