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Sum: 78x-126
Sum: x^2-2x-15
Products: 4(4x^2-6x+1)
Sum: 3x^2+10x-8
If we calculate the products, we can get their areas.
Now we can write the area of the generic rectangle as a sum. Sum: 78x-126
If we calculate the products we can get their areas.
Now we can write the area of the generic rectangle as a sum. Sum: x^2-2x-15
All three expressions share 2* 2 as factors. Therefore, we can let the vertical side of the generic rectangle have a length of 4 units.
Now the horizontal side of the thee rectangles can be identified as 4x, -6, and 1 respectively.
As we can see, the generic rectangle has a width of 4 units and a length of ( 4x^2 - 6x+ 1) units. With this information, we can write the area as a product by multiplying these dimensions. Product: 4( 4x^2 - 6x+ 1)
If we calculate the products we can get their areas.
Now we can write the area of the generic rectangle as a sum. Sum: 3x^2+10x-8