Core Connections Algebra 1, 2013
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Core Connections Algebra 1, 2013 View details
3. Section 11.3
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Exercise 136 Page 569

Practice makes perfect
a To create the generic rectangle, we will let each parentheses represent a side of the rectangle.

By multiplying the dimensions of the four rectangles, we can determine their individual areas.

The sum of the individual rectangles equals the sum of the bigger rectangle.
(5m-1)(m+2)=5m^2+10m+(- m)+(- 2)
(5m-1)(m+2)=5m^2+10m-m-2
(5m-1)(m+2)=5m^2+9m-2
b To create the generic rectangle, we will let each parentheses represent the sides of a rectangle.

By multiplying the dimensions of the four rectangles, we can determine their individual areas.

The sum of the individual rectangles equals the sum of the bigger rectangle.
(6-x)(2+x)=12+6x+(- 2x)+(- x^2)
(6-x)(2+x)=12+6x-2x-x^2
(6-x)(2+x)=12+4x-x^2
c Notice that we can rewrite this expression as two identical parentheses.

(5x-y)^2=(5x-y)(5x-y)

To create the generic rectangle, we will let each parentheses represent the sides of a rectangle.

By multiplying the dimensions of the four rectangles, we can determine their individual areas.

The sum of the individual rectangles equals the sum of the bigger rectangle.
(5x-y)^2=25x^2+(- 5xy)+(- 5xy)+y^2
(5x-y)^2=25x^2-5xy-5xy+y^2
(5x-y)^2=25x^2-10xy+y^2
d Note that we have one factor outside of the parentheses with three terms. This means the generic rectangle will be a 1* 3 rectangle

By multiplying the dimensions of the three rectangles, we can determine their individual areas.

The sum of the individual rectangles equals the sum of the bigger rectangle.
3x(2x-5y+4)=6x^2+(- 15xy)+12x
3x(2x-5y+4)=6x^2-15xy+12x