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Let's begin by gathering all constant terms on the right-hand side of the inequality. |x|+3 < 5 ⇔ |x|<2 Now, we can create a compound inequality by removing the absolute value. In this case, the solution set is any number less than 2 away from the midpoint in the positive direction and any number less than 2 away from the midpoint in the negative direction. Absolute Value Inequality:& |x| < 2 Compound Inequality:& - 2< x < 2 The graph of this inequality includes all values from - 2 to 2, not inclusive. We show this by using open circles on the endpoints.
Absolute Value Inequality:& |x+1| ≤ 4 Compound Inequality:& - 4≤ x+1 ≤ 4 We can split this compound inequality into two cases, one where x+1 is greater than or equal to -4 and one where x+1 is less than or equal to 4. x+1 ≥ - 4 and x+1 ≤ 4 Let's isolate x in both of these cases before graphing the solution set.
The solution to this type of compound inequality is the overlap of the solution sets. Let's recombine our cases back into one compound inequality. First Solution Set:& x ≤ 3 Second Solution Set:& - 5 ≤ x Intersecting Solution Set:& - 5 ≤ x ≤ 3
The graph of this inequality includes all values from - 5 to 3, inclusive. We show this by using closed circles on the endpoints.