Core Connections Algebra 1, 2013
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Core Connections Algebra 1, 2013 View details
2. Section 11.2
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Exercise 47 Page 543

Practice makes perfect
a Let's pay close attention to how the consecutive terms are related to each other.
We can see that the consecutive terms have a common difference of - 3. We also see that the first term is 7. Therefore, the given sequence is an arithmetic sequence with first term t(1)= 7 and common difference d= - 3. We can write its equation by substituting these values into the general equation for arithmetic sequences.
t(n)=t(1)+(n-1)d
t(n)= 7+(n-1)( -3)
t(n)=7 -3n +3
t(n)=- 3n+10
b Let's pay close attention to how the consecutive terms are related to each other.
We can see that the consecutive terms have a common ratio of 3. Therefore, the given sequence is an geometric sequence with common ratio r= 3. t( n)= t(1) r^(n-1) To find the equation for this sequence, we need to find the value of the first term. We can do it by substituting r=3 and t(2)=2000 in the equation.
t(n)=t(1)r^(n-1)
2000=t(1)* 3^(2-1)
â–Ľ
Solve for a_1
2000=t(1)* 3^1
2000=t(1)* 3
2000/3=t(1)
t(1)=2000/3
The first term of the sequence is 20003. Therefore, the equation for the given sequence can be written as follows. t( n)= t(1) r^(n-1) ⇓ t( n)= 2000/3 * 3^(n-1)