Core Connections Algebra 1, 2013
CC
Core Connections Algebra 1, 2013 View details
Chapter Closure

Exercise 145 Page 577

a

An equation in slope-intercept form follows a specific format.

y= mx+bFor an equation in this form, m is the slope and b is the y-intercept. Let's use the given points to calculate m. We will start by substituting the points into the Slope Formula.

m=y_2-y_1/x_2-x_1
m=2- 18/1-( - 1)
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Simplify right-hand side
m=- 16/1-(- 1)
m=- 16/2
m= - 8

A slope of -8 means that for every 1 horizontal step in the positive direction we take 8 vertical steps in the negative direction. Now that we know the slope, we can write a partial version of the equation. y= -8 x+b To complete the equation we also need to determine the y-intercept, b. Since we know that the given points will satisfy the equation, we can substitute one of them into the equation to solve for b. Let's use ( 1, 2).

y=- 8x+b
2=-8( 1)+b
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Solve for b
2=- 8+b
10=b
b=10

A y-intercept of 10 means that the line crosses the y-axis at the point (0,10). We can now complete the equation. y= - 8x+10

b

We want to find an exponential function that passes through (- 1, 18) and (1,2). To do this, we will create a system of equations by substituting ( x, y) = ( - 1, 18) into the general form of exponential function, y=ab^x, and then substituting again with ( x, y) = ( 1, 2).

18=a * b^(- 1) & (I) 2=a * b^1 & (II) We want to solve the above system of equations. When solving a system of equations using substitution, there are three steps.

  1. Isolate a variable in one of the equations.
  2. Substitute the expression for that variable into the other equation and solve.
  3. Substitute this solution into one of the equations and solve for the value of the other variable.

Observing the given equations, it looks like it will be simplest to isolate a in the first equation.

18=a * b^(- 1) & (I) 2=a * b^1 & (II)
18=a * b^(- 1) 2=a * b
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(I): Solve for a
18=a * 1b 2=a * b
18b=a 2=a * b
a=18b 2=a * b

Now that we have isolated a we can solve the system by substitution.

a=18b 2=a * b
a=18b 2= 18b * b
a=18b 2=18b^2
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(II): Solve for b
a=18b 218=b^2
a=18b 19=b^2
a=18b sqrt(19)=sqrt(b^2)
a=18b 13=b
a=18b b= 13

Great! Now, to find the value of a we need to substitute b= 13 into either one of the equations in the given system. Let's use the first equation.

a=18b b= 13
a=18( 13) b= 13
a= 183 b= 13
a=6 b= 13

The solution to this system of equations is a=6 and b=13. With this information, we can finally write an equation of the exponential function that passes through the given points. y=ab^x ⇔ y=6 (1/3)^x