Core Connections Algebra 1, 2013
CC
Core Connections Algebra 1, 2013 View details
Chapter Closure

Exercise 140 Page 575

a Using the function f(x), we want to find the expression f(x)+2. To do this, we will add 2 to the given function.
f(x)=2x^2
f(x)+ 2=2x^2+ 2
Now, let's look at all of the possible transformations so that we can more clearly identify what is happening to our function.
Transformations of f(x)
Vertical Translations Translation up k units, k>0 y=f(x)+ k
Translation down k units, k>0 y=f(x)- k
Horizontal Translations Translation right h units, h>0 y=f(x- h)
Translation left h units, h>0 y=f(x+ h)
Vertical Stretch or Compression Vertical stretch, a>1 y= af(x)
Vertical compression, 0< a< 1 y= af(x)
Horizontal Stretch or Compression Horizontal stretch, 0< b<1 y=f( bx)
Horizontal compression, b>1 y=f( bx)
Reflections In the x-axis y=- f(x)
In the y-axis y=f(- x)

As we can see, we can describe this transformation as a vertical translation 2 units up. It means that the graph of the given function was shifted 2 units up.

b Using the function f(x), we want to find the expression 2 * f(x). To do this, we will multiply the given function by 2 and simplify.
f(x)=2x^2
2 * f(x)= 2 * 2x^2
2 * f(x)=4x^2
We can describe this transformation as a vertical stretch by a factor of 2.
c Using the function f(x), we want to evaluate for the given value, f( x+2). To do this we need to substitute x+2 for x in each instance of the x-variable.
f(x)=2x^2
f( x+2)=2( x+2)^2
We can describe this transformation as a horizontal translation 2 units left. It means that the graph of the given function was shifted 2 units left.
d Using the function f(x), we want to evaluate for the given value, f( 2x). To do this we need to substitute 2x for x in each instance of the x-variable and simplify.
f(x)=2x^2
f( 2x)=2( 2x)^2
f(2x)=2 (2^2x^2 )
f(2x)=2 ( 4x^2 )
f(2x)=8x^2
We can describe this transformation as a horizontal stretch by a factor of 2.