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The expression on the left-side of the equation is given in the standard form of a quadratic function. Start by identifying the values of a, b, and c.
Solutions: x=- 1/2, x=- 9
Are the solutions the same? Yes.
We want to solve the given equation for x twice — once using the Zero Product Property and once using the Quadratic Formula. Then we will compare the answers.
We want to solve the given equation using the Zero Product Property. To do this, we need to rewrite the given equation in the factored form. We can start by using factoring.
c|c|c|c 1^(st)Factor &2^(nd)Factor &Sum &Result 1 & 18 & 1 + 18 &19 2 &9 &2 + 9 &11 3 &6 &3 + 6 &9
Factor out x
Factor out 9
Factor out (2x+1)
Use the Zero Product Property
(II): LHS-9=RHS-9
Substitute values
x=- 19± 17/4 | |
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x_1=- 19+17/4 | x_2=- 19-17/4 |
x_1=- 2/4 | x_2=- 36/4 |
x_1=- 1/2 | x_2=- 9 |
Using the Quadratic Formula, we found that the solutions are x_1=- 12 and x_2=- 9. Notice that those are the same solutions as obtained previously by factoring and then using Zero Product Property. Both methods are equally good, so they give the same solutions.