Core Connections Algebra 1, 2013
CC
Core Connections Algebra 1, 2013 View details
2. Section 10.2
Continue to next subchapter

Exercise 84 Page 500

Practice makes perfect
a To draw the graph of the given quadratic function written in standard form, we must start by identifying the values of a, b, and c.
f(x)=x^2-6x+5 ⇕ f(x)=1x^2+(- 6)x+5 We can see that a=1, b=- 6, and c=5. Now we will follow four steps to graph the function.
  1. Find the axis of symmetry.
  2. Calculate the vertex.
  3. Identify the y-intercept and its reflection across the axis of symmetry.
  4. Connect the points with a parabola.

Finding the Axis of Symmetry

The axis of symmetry is a vertical line with equation x=- b2a. Since we already know the values of a and b, we can substitute them into the formula.
x=- b/2a
x=- - 6/2(1)
â–Ľ
Simplify right-hand side
x=- - 6/2
x=6/2
x=3
The axis of symmetry of the parabola is the vertical line with equation x=3.

Calculating the Vertex

We can write the expression for the vertex by stating the x- and y-coordinates in terms of a and b. Vertex: ( - b/2a, f( - b/2a ) ) Note that the formula for the x-coordinate is the same as the formula for the axis of symmetry, which is x=3. Thus, the x-coordinate of the vertex is also 3. To find the y-coordinate, we need to substitute 3 for x in the given equation.
f(x)=x^2-6x+5
f(x)= 3^2-6( 3)+5
â–Ľ
Simplify right-hand side
f(x)=9-6(3)+5
f(x)=9-18+5
f(x)=- 4
We found the y-coordinate, and now we know that the vertex is (3,- 4).

Identifying the y-intercept and Its Reflection

The y-intercept of the graph of a quadratic function written in standard form is given by the value of c. Thus, the point where our graph intercepts the y-axis is (0,5). Let's plot this point and its reflection across the axis of symmetry.

Connecting the Points

We can now draw the graph of the function. Since a=1, which is positive, the parabola will open upwards. Let's connect the three points with a smooth curve.

We have already found that the vertex is (3, -4), which we identify on the above graph.

b The domain of quadratic functions is all real numbers. We can see on the graph in Part A that the minimum point of the curve is reached at the vertex. Thus, the range is all real numbers greater than or equal to - 4.

Domain:& All real numbers Range:& y ≥ - 4

c Looking at the graph the given function, we can tell that the parabola opens upwards.

The vertex is always the lowest or the highest point on the graph. Therefore, in this case, the vertex represents the minimum value of the function.