Exercise 1 Page 399

We want to evaluate the given expression. 2 + sqrt(27) We need to remember the order of operations. In this case, we will calculate the cube root. Then, we will add the terms. To find the cube root of 27. We need to think of a number that, when multiplied by itself three times, results in 27. ?^3= 27 Since 3 raised to the third power is 27, the number we are looking for is 3.

(3)(3)(3)

ProdToPowThreeFac

a* a* a=a^3

3^3

CalcPow

Calculate power

27

This means that the cube root of 27 is 3. 2 + sqrt(27) calculate root ⟶ 2+3 Finally, we can add the terms. 2 + 3 add ⟶ 5