We want to subtract the two given numbers.
11/6-0.27
Notice that one of the numbers is a repeating decimal and the other is a fraction. To subtract them, we need to have them in the same form, either both written as fractions or both written as decimals. We will get the same answer either way. Let's use the fraction method. Recall how to rewrite a repeating decimal as a fraction.
Write the equation x=d, where d is a repeating decimal.
Subtract the equation from the previous step from the equation 10^n x=10^n d, where n is the number of repeating digits.
Solve the equation for x.
We can use this process to rewrite - 0.27 as a fraction. We will substitute - 0.27 for d and 2 for n, as there are two repeating digits in the decimal.
ccc x=d & ⇔ & x= 0.27 10^nx=10^n d & ⇔ & 10^2x=10^2( - 0.27)
Let's simplify the second equation.
10^1x=10^2(- 0.27) ⇒ 100x=- 27.27
Now we are ready to subtract the first equation from the second one.
c r c l& 100x & = & - 27.27 -( & x & = & - 0.27 ) & 99x & = & - 27
Next, we can solve for x. Let's do it!
