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Evaluate each function for different values of l.
See solution.
We will make a table where the independent variable is the side length of a square and the dependent variable is the perimeter. To do so, let's start by recalling the perimeter of a square. P=4l Here, l is the side length of the square. Now, we can evaluate this formula for several values of l.
l | P=4l | P |
---|---|---|
0 | P=4( 0) | 0 |
2 | P=4( 2) | 8 |
4 | P=4( 4) | 16 |
6 | P=4( 6) | 24 |
These points lie on a line. Consider that the value of l indicates the value of x and its corresponding value of P represents the value of y. These values form a ordered pair that can be plotted in a coordinate plane. Let's plot the ordered pairs and draw a line through the points.
Now, we can recall the formula for the area of a square. A=l^2 Let's evaluate this formula for several values of l and construct a table with the results.
l | A=l^2 | A |
---|---|---|
0 | A=( 0)^2 | 0 |
2 | A=( 2)^2 | 4 |
4 | A=( 4)^2 | 16 |
6 | A=( 6)^2 | 36 |
In this case, consider that the value of l indicates the value of x and its corresponding value of A represents the value of y. Let's plot the ordered pairs and draw a curve through the points.
Now, we can plot the obtained curves in the same coordinate plane.
Notice that the graph of the perimeter is a line, but the graph of the area is a curve. This means that the perimeter is a linear function of the side of the square and the area is a non-linear function of the side lenght.