Big Ideas Math: Modeling Real Life, Grade 8
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Big Ideas Math: Modeling Real Life, Grade 8 View details
3. Solving Systems of Linear Equations by Elimination
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Exercise 26 Page 217

Are there any variables isolated?

Solution: (2,-1)
Method: See solution.

Practice makes perfect
Since the y-variable is already isolated, the easiest way to solve the system of equations is to use the Substitution Method. Let's substitute y=x-3 into the second equation.
y=x-3 & (I) y=-2x+3 & (II)
y=x-3 x-3=-2x+3
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Solve for x
y=x-3 x-3+2x=-2x+3+2x
y=x-3 3x-3=3
y=x-3 3x-3+3=3+3
y=x-3 3x=6
y=x-3 3x/3=6/3
y=x-3 3/3 * x=6/3
y=x-3 1 * x=6/3
y=x-3 x=6/3
y=x-3 x=2
Great! Now, to find the value of y, we need to substitute x=2 into either one of the equations in the given system. Let's use the first equation.
y=x-3 x=2
y= 2-3 x=2
y=-1 x=2
The solution, or point of intersection, to this system of equations is the point (2,-1).