Big Ideas Math: Modeling Real Life, Grade 8
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7. Perimeters and Areas of Similar Figures
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Exercise 6 Page 87

To find the image of a vertex after a dilation using a scale factor k, multiply its coordinates by k.

Ratio of Perimeters: 3
Ratio of Areas: 9

Practice makes perfect

Let's start by plotting the given points and connecting them with segments to draw the triangle.

A dilation can be an enlargement or a reduction of the preimage. Which type of dilation it is depends on the value of the scale factor k.

Enlargement k>1
Reduction 0

When the center of dilation in the coordinate plane is the origin, each coordinate of the preimage is multiplied by the scale factor k to find the coordinates of the image. ccc Preimage & & Image [0.5em] (x,y)& ⇒ & ( kx, ky) Now, let's find the coordinates of the vertices of the triangle after a dilation with a scale factor k= 3.

Dilation With Scale Factor k=3
Preimage Multiply by k Image
(0,0) ( 3(0), 3(0)) (0,0)
(0,2) ( 3(0), 3(2)) (0,6)
(2,0) ( 3(2), 3(0)) (6,0)
Now we can plot the new points on the coordinate plane and connect them with segments to draw the image. Let's do it!
dilation
We want to find the ratio of the perimeters of the two figures. Remember that when two figures are similar, the value of the ratio of their perimeters is equal to the value of the ratio of their corresponding side lengths. Perimeter of Image/Perimeter of Preimage=Side Length Image/Side Length Preimage In our case, one of the side lengths of the original triangle is 2 and its corresponding side length is 6. Let's substitute these values into the above equation to find the ratio between the perimeters.
Perimeter of Image/Perimeter of Preimage=Side Length Preimage/Side Length Image
Perimeter of Image/Perimeter of Preimage=6/2
Perimeter of Image/Perimeter of Preimage=3
The ratio of the perimeter of the image to the perimeter of the preimage is 3. Now we can find the ratio of the areas. Recall that when two figures are similar, the value of the ratio of their areas is equal to the square of the value of the ratio of their corresponding sides lengths. Area of Image/Area of Preimage=(Side Length Image/Side Length Preimage)^2 Again, one of the side lengths of the original triangle is equal to 2 and its corresponding side length is 6. Let's substitute these values into the above equation to find the ratio between the areas.
Area of Image/Area of Preimage=(Side Length Image/Side Length Preimage)^2
Area of Image/Area of Preimage=(6/2)^2
Area of Image/Area of Preimage=(3)^2
Area of Image/Area of Preimage=9
The ratio of the area of the image to the area of the preimage is 9.