Big Ideas Math: Modeling Real Life, Grade 8
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Big Ideas Math: Modeling Real Life, Grade 8 View details
3. Volumes of Spheres
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Exercise 6 Page 441

Consider the given sphere.

The volume of a sphere is four thirds the product of π and the cube of the radius. V=4/3π r^3 In the diagram we can see that the volume is 4500π cubic yards. Therefore, we can substitute 4500π for V in the above formula and solve it for r.
V=4/3π r^3
4500π=4/3π r^3
Evaluate right-hand side
4500π=4 π r^3/3
3* 4500π = 3 * 4 π r^3/3
3* 4500π = 4 π r^3
13 500π = 4 π r^3
13 500π/4π=4 π r^3/4π
13 500π/4π=4π r^3/4π
13 500π/4π=r^3
3375π =r^3
sqrt(3375π)=sqrt(r^3)
sqrt(3375π)=r
r=sqrt(3375π)
r=21.968878...
r≈ 22
The radius of the sphere, correct to the nearest tenth, is 22 yards.