a Draw a simple map and place each location in relation to each other.
B
b Calculate the unknown distance by combining the ones that are known.
C
c Calculate the unknown distance by combining the ones that are known.
D
d Use the Distance Rate Time Formula.
A
a The post office.
B
b 416 yards.
C
c 1305 yards.
D
d ≈ 17.5 minutes.
Practice makes perfect
a Let's start by making a rough sketch of the road from the school S to home H. On this map, let's also add the approximate position of the post office P and the grocery store G. We know that both the post office and the grocery store are in between school and home, and that the post office is farther away from home than the grocery store.
Let's now add the given distances to our sketch.
From the sketch, we can see that the post office is closer to school than the grocery store. Thus, we should stop their first.
b From our sketch in Part A, we can see that the distance between the post office and home can be broken up into the distance from the post office to the grocery store and the distance from the grocery store to home. PH = PG + GH
Since we know PH=929 and GH=513, we can substitute these values into the above equation and solve for PG.
Thus, the distance from the post office to the grocery store is 416 yards.
c From our sketch in Part A, we can see that the distance between school and home is comprised of the distance from school to the post office and the distance beween the post office and home. SH = SP + PH
Since we know SP=376 and PH=929, we can add these values together to get the total distance between school and home.
SH= SP+ PH= 376+ 929=1305 yards.
d To determine the time it takes to walk home from school, we can use the Distance Rate Time Formula.
d=r* t ⇒ d/r=t
With a distance of d= 1305 yards and a speed of r= 75 yards per minute, the time it takes to walk home is
1305/75 =17.4 minutes.
It takes approximately 17 and a half minutes to walk home.
