Exercise 35 Page 170

Let's start by reflecting line l in the x-axis. This will give us the graph of line k. Note that symmetric points will have the same x-coordinate, but their y-coordinates will have opposite signs.

To find the equation of line k, we need to find its slope and y-intercept. We see above that line k intercepts the y-axis at the point (0, - 1). Therefore, the y-intercept is - 1. y= mx+( - 1) ⇔ y= mx-1 To find the slope m, we will substitute two of its points, (0,- 1) and (3,4), in the Slope Formula.

m=y_2-y_1/x_2-x_1

SubstitutePoints

Substitute ( 0,- 1) & ( 3,4)

m=4-( - 1)/3- 0

SubNeg

a-(- b)=a+b

m=4+1/3-0

AddSubTerms

Add and subtract terms

m=5/3

Now that we know the slope is m= 53, we can write the equation of line k. y= 5/3x-1