Chapter Test
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Point-slope form is y-y_1=m(x-x_1).
Example Solution: y-2=- 1/3(x+3)
Equations in point-slope form follow a specific format.
y- y_1= m(x- x_1)
In this form, m is the slope of the line and ( x_1, y_1) is a point on the line.
Here we are given that the line passes through two known points.
Substitute ( 6, - 1) & ( - 3, 2)
a-(- b)=a+b
Add and subtract terms
a/b=.a /3./.b /3.
Put minus sign in front of fraction
Now that we know the slope of the line is - 13, we can write the equation of the line in point-slope form. We can use either of the given points as (x_1,y_1) in our equation. Let's use ( - 3, 2).
Substitute values
a-(- b)=a+b
Please note that any point on the line can be used to form a point-slope equation. Therefore, our equation is only one of infinitely many possible equations!
Distribute - 1/3
a/3* 3 = a
LHS+2=RHS+2