Big Ideas Math Integrated I, 2016
BI
Big Ideas Math Integrated I, 2016 View details
Cumulative Assessment

Exercise 5 Page 161

We can substitute the x and y-intercepts into the equation to solve for a and b.

a=-4, b=5

Practice makes perfect
To solve for a and b, we can substitute the x and y-intercepts into the equation. Let's look at each situation individually.


Solve for a

To solve for a, we can substitute the x-intercept into the equation. We are given that the x-intercept is -10. Since the x-intercept occurs when the function crosses the x-axis, we know that the point is (-10,0).
ax+by=40
a( -10)+b* 0=40
-10a=40
a=-4

Solve for b

To solve for b, we can substitute the y-intercept into the equation. We are given that the y-intercept is 8. Since the y-intercept occurs when the function crosses the y-axis, we know that the point is (0,8).
ax+by=40
a* 0+b* 8=40
8b=40
b=5