Exercise 7 Page 537

Both angles are on the outside of the lines and on opposite sides of the transversal. Therefore, the angles can be classified as alternate exterior angles. According to the Alternate Exterior Angles Converse, if the angles are congruent, the lines are parallel. We can thus write the equation. 8x=4x+24 Let's solve this equation.

8 x = 4 x + 24

SubEqn

LHS-4 x=RHS-4 x

4 x = 24

DivEqn

.LHS /4.=.RHS /4.

x = 6

When x=6, m ∥ n.