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To classify the triangle by its sides, you need to know their lengths. To determine if the triangle is a right triangle, you need to know the slopes of the sides.
Classify by sides: Scalene triangle
Right triangle? Yes
Let's start by drawing the triangle in a coordinate plane.
Substitute ( -2,3) & ( 0,-3)
a-(- b)=a+b
Subtract term
Calculate power
Add terms
Split into factors
sqrt(a* b)=sqrt(a)*sqrt(b)
Calculate root
Side | Points | sqrt((x_2-x_1)^2+(y_2-y_1)^2) | Length |
---|---|---|---|
AB | ( -2,3) & ( 0,-3) | sqrt(( 0-( -2))^2+( -3- 3)^2) | 2sqrt(10) |
AC | ( -2,3) & ( 3,-2) | sqrt(( 3-( -2))^2+( -2-( 3))^2) | 5sqrt(2) |
BC | ( 0,-3) & ( 3,-2) | sqrt(( 3- 0)^2+( -2-( -3))^2) | sqrt(10) |
As we can see, all the lengths are different. This means △ ABC is scalene.
In our diagram, we see that ∠ A and ∠ C are acute angles. In order for △ ABC to be a right triangle, ∠ B must be a right angle. To determine if this is the case, we will first calculate the slope of AB and BC using the Slope Formula.
Side | Points | y_2-y_1/x_2-x_1 | Slope | Simplified Slope |
---|---|---|---|---|
AB | ( - 2,3) & ( 0,-3) | -3- 3/0-( - 2) | - 6/2 | - 3 |
BC | ( 0,-3) & ( 3,-2) | -2-( -3)/3- 0 | 1/3 | 1/3 |
Since -3 and 13 are opposite reciprocals, we know that AB is perpendicular to BC. Therefore, △ ABC is in fact a right triangle.