Big Ideas Math Geometry, 2014
BI
Big Ideas Math Geometry, 2014 View details
3. Two-Way Tables and Probability
Continue to next subchapter

Exercise 18 Page 689

Make a two-way table of relative frequencies. Then calculate the conditional probability of completing tasks above the expectations for each group.

Group 1, see solution.

Practice makes perfect

We want to find which group should be awarded the prize. To do so, we will calculate the conditional probability of completing tasks above the expectations for every group.

Making a Two-Way Table of Frequency Counts

First we will use the given table of records made by the teacher to make a two-way table of frequency counts. If we count the segments and write the results as numbers, we will get a table that shows the joint frequencies.

two way table with joint frequencies
To calculate the marginal frequencies we will sum the values in the columns and rows.
two way table with joint and marginal frequencies

Now we know marginal frequencies and total sum of all tasks, which is 44.

Making a Two-Way Table of Relative Frequencies

To find the joint and marginal relative frequencies we will divide the values in every cell in the table by the total number of tasks.

calculating relative frequencies in two way table

Let's evaluate these expressions and round the results to the nearest hundredths.

two way table of relative frequencies

Calculating the Conditional Probabilities

Finally, we will find the conditional probability of completing the tasks while exceeding the expectations for every group. Let's remember the formula for conditional probability. P(B|A)=P(AandB)/P(A) Event B in the formula is completing the task above the expectations, and Event A is choosing Group A for the task. We will divide the joint relative frequency from the column Exceed Expectations by the marginal frequency in the corresponding row to get the conditional probability for every group. We will start with Group 1.
P(Group1and Exceed Expectations)/P(Group1)
0.27/0.36
0.75
Now we will do similar calculations for Group 2.
P(Group2and Exceed Expectations)/P(Group2)
0.18/0.30
0.6
Finally, we will repeat these calculations for Group 3.
P(Group3and Exceed Expectations)/P(Group3)
0.20/0.34
â–Ľ
Evaluate
0.5882...
0.58
Basing on the sample, we obtained that Group 1 has the greatest probability of completing tasks and exceeding the expectations. Therefore, the teacher should choose Group 1 to be awarded the prize.