Big Ideas Math Geometry, 2014
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Big Ideas Math Geometry, 2014 View details
3. Two-Way Tables and Probability
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Exercise 6 Page 687

Recall that if P(B) and P(B|A) are equal, A and B are independent events.

Yes, see solution.

Practice makes perfect

We want to determine if recommending the provider to a friend and living in Santa Monica are independent events. To do so we will use the given two-way table.

two way table categories

At first we will define two events, which will be useful in further calculations.

  • A — a customer recommends the provider.
  • B — a customer is located in Santa Monica.We will use the property that if P(B) and P(B|A) are equal, A and B are independent events. P(B) ? = P(B|A) To find P(B), which is the probability that the customer is from Santa Monica, we will calculate the marginal relative frequency of the second column of the table. P(B)=0.27+0.03 ⇔ P(B)= 0.3 To evaluate the right hand side of the equation we will use the formula for the conditional probability. P(B|A)=P(AandB)/P(A) We know that a customer is located in Santa Monica and will recommend the provider with a probability of 0.27, which corresponds with P(AandB). P(AandB)= 0.27 To find P(A), which is the probability that the customer will recommend the provider to a friend, we will calculate the marginal relative frequency of the first row of the table. P(A)=0.29+0.27+0.32 ⇔ P(A)= 0.88 With this information we can calculate P(B|A).
    P(B|A)=P(AandB)/P(A)
    P(B|A)=0.27/0.88
    P(B|A)=0.3068...
    P(B|A)≈ 0.3
    We obtained that P(B) ≈ P(B|A), so recommending the provider to a friend and living in Santa Monica are independent events.