Big Ideas Math Geometry, 2014
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Big Ideas Math Geometry, 2014 View details
3. Two-Way Tables and Probability
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Exercise 15 Page 689

To find the marginal frequency of the event you need to add all joint frequencies of the event.

Error: 0.356 is the probability of response Yes, and the probability of living in Tokyo is 0.39.
Correct Answer: About 0.126

Practice makes perfect

We want to describe the error in finding the conditional probability.

We will check the calculations step by step, starting from verifying the formula for the conditional probability. P(B|A)=P(AandB)/P(A)

In our case event B is marking response Yes on the survey, and event A is living in Tokyo. Therefore, the formula was used properly. Now we will check the values of P(AandB) and P(A). Let's look at the given two-way table.

two way table
We know that a person lives in Tokyo and marked response Yes on the survey with a probability of 0.049, which is the value of the cell at the intersection of row Yes and the Tokyo column. It corresponds with P(Tokyo and Yes). P(Tokyo and Yes)= 0.049 Now we will find P(Tokyo), which is the probability that a person lives in Tokyo. As we can see, the value of this marginal relative frequency of the first column is 0.39. The incorrect value in the calculations, 0.356, is the marginal relative frequency of the first row, which corresponds with the marking response Yes on the survey (P(Yes)). P(Tokyo)= 0.39 With this information, we can calculate P(Yes|Tokyo) correctly.
P(Yes|Tokyo)=P(Tokyo and Yes)/P(Tokyo)
P(Yes|Tokyo)=0.049/0.39
P(Yes|Tokyo)=0.125641...
P(Yes|Tokyo)≈ 0.126
The probability that a randomly selected person from Tokyo marked response Yes on the survey is about 0.126.