Sign In
m∠ABD=67^(∘)
m∠CBD=67^(∘)
m∠ABC=134^(∘)
We are asked to find three angle measurements: m∠ABC, m∠ABD, and m∠CBD. We have been told that BD bisects ∠ABC which means that it cuts the angle exactly in half. We have marked these relationships in the diagram below. Let's consider them.
Since BD bisects angle ∠ABC, angles ∠ABD and ∠DBC have the same measure. This means that m∠ABD=m∠DBC. Therefore, we can form an equation and substitute the given expressions for the measures to solve for x.
m∠ABD= 8x+35, m∠CBD= 11x+23
LHS-11x=RHS-11x
LHS-35=RHS-35
LHS * (- 1)=RHS* (- 1)
.LHS /3.=.RHS /3.
Having solved the equation, we can calculate the measures of individual angles by substituting x= 2 into the given expressions. m∠ABD:& 8( 4)+35 =67^(∘) m∠CBD:& 11( 4)+23 =67^(∘) Having found m∠ABD and m∠CBD, we can find m∠ABC. Since this angle is bisected by BD, its measure can be calculated by doubling either of the smaller angles. m∠ABC: 67* 2 = 134^(∘)