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m∠ABD=24^(∘)
m∠CBD=24^(∘)
m∠ABC=48^(∘)
We are asked to find three angle measurements: m∠ABC, m∠ABD, and m∠CBD. We have been told that BD bisects ∠ABC which means that it cuts the angle exactly in half. We have marked these relationships in the diagram below. Let's consider them.
Since BD bisects angle ∠ABC, angles ∠ABD and ∠DBC have the same measure. This means that m∠ABD=m∠DBC. Therefore, we can form an equation and substitute the given expressions for the measures to solve for x.
m∠ABD= 3x+6, m∠CBD= 7x-18
LHS-7x=RHS-7x
LHS-6=RHS-6
LHS * (- 1)=RHS* (- 1)
.LHS /4.=.RHS /4.
Having solved the equation, we can calculate the measures of individual angles by substituting x= 6 into the given expressions. m∠ABD:& 3( 6)+6 =24^(∘) m∠CBD:& 7( 6)-18 =24^(∘) Having found m∠ABD and m∠CBD, we can find m∠ABC. Since this angle is bisected by BD, its measure can be calculated by doubling either of the smaller angles. m∠ABC: 24* 2 = 48^(∘)