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m∠ABD=65^(∘)
m∠CBD=65^(∘)
m∠ABC=130^(∘)
We are asked to find three angle measurements: m∠ABC, m∠ABD, and m∠CBD. We have been told that BD bisects ∠ABC which means that it cuts the angle exactly in half. We have marked these relationships in the diagram below. Let's consider them.
Since BD bisects angle ∠ABC, angles ∠ABD and ∠DBC have the same measure. This means that m∠ABD=m∠DBC. Therefore, we can form an equation and substitute the given expressions for the measures to solve for x.
m∠ABD= - 4x+33, m∠CBD= 2x+81
LHS-2x=RHS-2x
LHS-33=RHS-33
.LHS /(- 6).=.RHS /(- 6).
Having solved the equation, we can calculate the measures of individual angles by substituting x= - 8 into the given expressions. m∠ABD:& - 4( -8)+33 =65^(∘) m∠CBD:& 2 ( - 8)+81 =65^(∘) Having found m∠ABD and m∠CBD, we can find m∠ABC. Since this angle is bisected by BD, its measure can be calculated by doubling either of the smaller angles. m∠ABC: 65* 2 = 130^(∘)