1. Defining and Using Sequences and Series
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Substitute values for n=1, 2, 3, 4, 5, and 6 to find the first 6 terms.
1, 2/3, 3/5, 4/7, 5/9, 6/11
f(n)= n/2n-1 To do so we will construct a table.
n | f(n)=n/2n-1 | f(n) |
---|---|---|
1 | f( 1)=1/2( 1)-1 | 1 |
2 | f( 2)=2/2( 2)-1 | 2/3 |
3 | f( 3)=3/2( 3)-1 | 3/5 |
4 | f( 4)=4/2( 4)-1 | 4/7 |
5 | f( 5)=5/2( 5)-1 | 5/9 |
6 | f( 6)=6/2( 6)-1 | 6/11 |
The first 6 terms of this explicit sequence are 1, 23, 35, 47, 59, and 611.