1. Defining and Using Sequences and Series
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Substitute values for n=1, 2, 3, 4, 5, and 6 to find the first 6 terms.
16, 25, 36, 49, 64, and 81
a_n= (n+3)^2 To do so we will construct a table.
n | a_n=(n+3)^2 | a_n |
---|---|---|
1 | a_1=( 1+3)^2 | 16 |
2 | a_2=( 2+3)^2 | 25 |
3 | a_3=( 3+3)^2 | 36 |
4 | a_4=( 4+3)^2 | 49 |
5 | a_5=( 5+3)^2 | 64 |
6 | a_6=( 6+3)^2 | 81 |
The first 6 terms of this explicit sequence are 16, 25, 36, 49, 64, and 81.