Big Ideas Math Algebra 2, 2014
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Big Ideas Math Algebra 2, 2014 View details
8. Analyzing Graphs of Polynomial Functions
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Exercise 2 Page 212

Use the Zero Product Property to find the zeros of the polynomial function.

Practice makes perfect

We want graph the given polynomial function. f(x)=1/4(x+2)(x-1)(x-3) Let's start by finding its zeros.

Zeros of the Function

To do so, we need to find the values of x for which f(x)=0. f(x)=0 ⇔ 1/4(x+2)(x-1)(x-3)=0 Since the function is already written in factored form, we will use the Zero Product Property. Notice, we do not set the coefficient 14 equal to zero as it produces a false statement.
(x+2)(x-1)(x-3)=0
lcx+2=0 & (I) x-1=0 & (II) x-3=0 & (III)
lx=- 2 x-1=0 x-3=0
lx=- 2 x=1 x-3=0
lx=- 2 x=1 x=3
We found that the zeros of the function are - 2, 1, and 3.

Graph

To draw the graph of the function, we will find some additional points and consider the end behavior. Let's use a table to find additional points.

x 1/4(x+2)(x-1)(x-3) f(x)=1/4(x+2)(x-1)(x-3)
- 3 1/4( - 3+2)( - 3-1)( - 3-3) - 6
- 1 1/4( - 1+2)( -1-1)( -1-3) 2
0 1/4( 0+2)( 0-1)( 0-3) 1.5
2 1/4( 2+2)( 2-1)( 2-3) - 1
4 1/4( 4+2)( 4-1)( 4-3) 4.5
The points ( - 3, - 6), ( - 1, 2), ( 0, 1.5), ( 2, -1), and ( 4, 4.5) are on the graph of the function. Finally, let's apply the Distributive Property. This will simplify the equation and determine the leading coefficient and degree of the polynomial function.
y=1/4(x+2)(x-1)(x-3)
â–Ľ
Distribute (x-3) & Simplify
y=1/4(x+2)(x(x-3)-1(x-3))
y=1/4(x+2)(x^2-3x-1(x-3))
y=1/4(x+2)(x^2-3x-x+3)
y=1/4(x+2)(x^2-4x+3)
â–Ľ
Distribute (x+2) & Simplify
y=1/4(x^2(x+2)-4x(x+2)+3(x+2))
y=1/4(x^3+2x^2-4x(x+2)+3(x+2))
y=1/4(x^3+2x^2-4x^2-8x+3(x+2))
y=1/4(x^3+2x^2-4x^2-8x+3x+6)
y=1/4(x^3-2x^2-5x+6)
â–Ľ
Distribute 1/4 & Simplify
y=1/4(x^3)+1/4(-2x^2)+1/4(-5x)+1/4(6)
y=1/4x^3 - 1/2x^2- 5/4x +3/2
We can see now that the leading coefficient is 14, which is a positive number. Also, the degree is 3, which is an odd number. Therefore, the end behavior is down and up. Now, let's draw the graph!